what is that max torque it can with stand when the max laod it can handle is 811 N?i can NOT get this question, its driving me crazy!HELP????? thank you
The easy answer is that the applied torque is the cross product of the radial arm and the force, or in this case T = 811*17*cos(13.5). The hard (it's actually not that hard) answer will depend on the design and material properties of the crane. Since the problem asks for max torque, I'd find the bending stress due to the moment found above (T = 811*17*cos(13.5)) where bending stress = Ty/I. Next, compare this to the yield stress of the crane's material and an appropriate failure criterion.
torque depends on the distance between the line of action of the force and the axis of rotation of the body. the unit of torque in SI unit is newton-metre. t=fd t=17*811 t=13787
I don't know if this is a question you got out of a book, or something you are trying to apply on a jobsite, but I would hate to see you try and use this approach with expensive equipment and innocent lives in the balance. Learn to use the crane charts. They account for many factors, including the weight of the boom, the tipping moment, the strength of the ropes, the engine's power, and the structural integrity of the boom.
