Home > categories > Minerals & Metallurgy > Iron Ore > The following unbalanced equation shows one of the steps in the process of reducing iron ore to iron metal.?
Question:

The following unbalanced equation shows one of the steps in the process of reducing iron ore to iron metal.?

The following unbalanced equation shows one of the steps in the process of reducing iron ore to iron metal.Fe2O3(s) + CO(g) → Fe(s) + CO2(g)If you begin with 627 grams of iron(III) oxide and an excess of CO, what is the maximum number of grams of Fe that can be obtained?

Answer:

First balance the equation Fe2O3 plus 3CO yields 2Fe plus 3CO2 Then over the iron III oxide in the above equation place 627 grams. And under the iron oxide place the sum of its atomic weights. 2 x 56 and 3x l0 Now over the 2Fe on the product side place X grams, and under the 2Fe place the sum of its atomic wts. 2x 56. now cross multiply and solve for X grams of Fe.
some air breathers have a hole in the bottom to mount that back to
Tjis filters out dirt while taking in air ti mix with gas to combust. The whole should have a sensor plugged in it to allow for computer to pick up more free flow air and adjust mixture so your air intake is not just show.
in simple terms the bullet? everywhere from 29 grains (no longer grams; interior the united states, bullet weight is measured in grains) as much as over 3 hundred grains, probably. it particularly relies upon on the cartridge and shipment in question. A .22 short, which may well be utilized in some .22-high quality revolvers, normally makes use of a 29 grain bullet. A .500 SW Magnum, that's the main useful modern-day handgun cartridge, can use bullets of three hundred grains or greater. That quantities to someplace around 2 grams as much as over 18 grams. lower back, that's in simple terms pondering the particularly projectile (i.e., the bullet), no longer the entire cartridge, which incorporates the casing, primer, and powder. EDIT: Raoul Duke's scale might desire to be poorly calibrated. The a hundred and fifteen grain bullet (in simple terms the bullet) utilized by potential of many 9mm Parabellum cartridges is fairly over one gram.
First balance the equation Fe2O3 plus 3CO yields 2Fe plus 3CO2 Then over the iron III oxide in the above equation place 627 grams. And under the iron oxide place the sum of its atomic weights. 2 x 56 and 3x l0 Now over the 2Fe on the product side place X grams, and under the 2Fe place the sum of its atomic wts. 2x 56. now cross multiply and solve for X grams of Fe.
some air breathers have a hole in the bottom to mount that back to
Tjis filters out dirt while taking in air ti mix with gas to combust. The whole should have a sensor plugged in it to allow for computer to pick up more free flow air and adjust mixture so your air intake is not just show.
in simple terms the bullet? everywhere from 29 grains (no longer grams; interior the united states, bullet weight is measured in grains) as much as over 3 hundred grains, probably. it particularly relies upon on the cartridge and shipment in question. A .22 short, which may well be utilized in some .22-high quality revolvers, normally makes use of a 29 grain bullet. A .500 SW Magnum, that's the main useful modern-day handgun cartridge, can use bullets of three hundred grains or greater. That quantities to someplace around 2 grams as much as over 18 grams. lower back, that's in simple terms pondering the particularly projectile (i.e., the bullet), no longer the entire cartridge, which incorporates the casing, primer, and powder. EDIT: Raoul Duke's scale might desire to be poorly calibrated. The a hundred and fifteen grain bullet (in simple terms the bullet) utilized by potential of many 9mm Parabellum cartridges is fairly over one gram.

Share to:

Hot Tag