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Question:

The sum of an integer and the square of its additive inverse is 56. What is the number?

Pls. help me answer this math wizards, I need a solution in this problem. Thanks!

Answer:

x + (-x)^2 56 (-x)^2 + x - 56 0 (-x + 7) (-x - 8) 0 (-x + 7) 0 x 7 (-x - 8) 0 x -8 7 + 49 56 -8 + 64 56
The number would be 7, how you find this is that you take 7*7 49, then take 49 + 7 56!
If x is the number, then -x is the additive inverse. Thus: (-x)^2 + x 56 x^2 + x - 56 0 (x + 8)(x - 7) 0 x -8 or 7 If you check them, both solutions work, so we can't narrow the possibilities for the integer any further than these two possibilities.

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