Find the transformer ratio of a transformer having 350 turns on the secondary winding and 7000 turns on the primary. What RMS voltage must be applied to the primary of the transformer to develop an open-circuit secondary voltage of 63 V? if a load of 100 ohms is connected to the secondary winding what is the primary current, ignoring resistive and reactive losses in the transformer?
Primary/secondary ratio 7000/350 20/1 For 63 V on secondary: Primary volts 20 * 63 1260 V.
Same results as Electronbut in a different way. 7000 primary turns divided by 350 secondary turns, 20:1 ratio 63 volts on secondary times ratio of 20 1260 volts on primary. 63 volts divided by 100 ohms 0.63 amps on secondary. 0.63 amps on secondary divided by ratio of 20 .0315 amps on primary.
you're on the outstanding song with the remark approximately ratios. yet another substantial ratio is the impedance ratio of a transformer, that's the sq. of the turns ratio. So, in case you have a prevalent with 12.6K and a secondary with 8.05, then you definately've an impedance ratio of (12600 / 8.05) 1565.2 and hence the turns ratio would desire to be the sq. root of this, or 39.fifty six. i think of that, given the above, you could decide section B now, outstanding?
Transformer ratio (number of windings on secondary) / (number of windings on primary) Transformer ratio 350 / 7000 1/20 And Transformer ratio (secondary voltage) / (primary voltage) 1/20 63 / (primary voltage) Primary voltage 20 * 63 1260 volts if a load of 100 ohms is connected to the secondary winding what is the primary current, ignoring V I * R 63 I * 100 Secondary current 0.63 amps Ignoring resistive and reactive losses in the transformer, the power coming out of the transformer is equal to the power coming into the transformer. Power Voltage * Current Secondary voltage * Secondary current Primary voltage * Primary current 63 * 0.63 1260 * Primary current Primary current 63 * 0.63 ÷ 1260 0.0315 amps
