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transformers - physics!!!!! HELP?

A step up transformer increases 17.7v to 120v. what is the ratio of the current in the secondary compared to primary? Assume 92% efficiency.HELP PLEASE

Answer:

Preliminary necessary comments. (i) This question - and consequently my answer - assumes that we have a perfect transformer: such a transformer will have an efficiency of 100 %. (If this was not a perfect transformer, then a great deal more data about the transformer would need to be supplied: it isn't). Hence, because the efficiency of the transformer in this question is less than 100%, that must be because a secondary current is flowing in the load, the details of which we do not know - or indeed need to know. (ii) Transformers are rated in terms of their product of volts and amps: called VA. They are NOT rated in terms of watts, since the manufacturer cannot assume that the load on the transformer secondary will have a unity power factor. (iii) When a transformer supplies current to a load, its on-load efficiency is the ratio of (VA)out to (VA)in. (VA)in primary VA; (VA)out secondary VA. Solution. Let the primary current Ip; let the secondary current Is. Let the primary voltage Vp; let the secondary voltage Vs. Let the efficiency n. Then we have: (VA)in Ip X Vp Ip X 17.7 (VA)out Is X Vs Is X 120. (VA)out n X (VA)in. so: Is X 120 0.92 X Ip X 17.7 i.e.: Is/Ip (0.92 X 17.7)/120 0.138/1 ? Hence, the secondary current is 0.138 that of the primary current. HTH, Skywave.
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Sec Curren Ratiot 17.7/(120*0.92) 0.136

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