What are the most effective circumferential forces that can be transmitted by belt transmission?
A - wrap angle on belt pulley, alpha =min (a_1, alpha _2), rad.A_1 = 180^ ~ - (d_d2-d_d1) 57.5^ ~ /aA_2 = 180^ ~ + (d_d2-d_d1) 57.5^ ~ /aD_d1 and d_d2 are a small pulley and pulley datum diameter. For the V belt, the reference diameter is the sheave width, and the width is equal to the diameter of the band width b_p.From the upper model, the minimum initial tension directly determines the magnitude of the critical friction force. It is also noted that increasing the friction coefficient (or equivalent friction coefficient) and the pack angle of the pulley can increase the critical frictional force, thereby minimizing the minimum Flali (F_0) _min value.
Now, let's say the minimum initial tension, the critical friction force, the friction coefficient, the angle of the package, the relation between them. Under the influence of the minimum Flali (F_0) _min, the maximum total friction between the belt and the pulley is the frictional force that drives the belt to be slipping. It is called the critical friction force F_fc or the critical effective tension F_ec. According to the theoretical deduction, the relation between them is...F_ec=F_fc=2 (F_0) _min (1-1/e^fa) / (1+1/e^fa)Formula: F - the coefficient of friction (when the working surface of the belt is not flat, should use the equivalent coefficient of friction f_v);
First of all, we should know that belt drive is a kind of flexible transmission. It is a kind of transmission that uses the friction or meshing between pulleys and belts to transfer the motion.
