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Question:

What formula is used to solve this?

Spent steam from an electric generating plant leaves the turbines at 120 degrees C and is cooled to 90 degrees C liquid water by water from a cooling tower in a heat exchanger. How much heat is removed by the cooling tower for each kg of spent steam?

Answer:

specific heat water is 4186 J/kgC heat of vaporization of water is 2.256 MJ/kg specific heat of steam is 2100 J/kgK energy is removed to cool it to 100 C (assuming atmospheric pressure), then energy to condense it to liquid, then more to cool it from 100 to 90 C part 1) E = 2100 J/kgK x 1kg x 20C = 42000 J part 2) E = 2.256 MJ/kg x 1kg = 2256000 J part 3) E = 4186 J/kgC x 1 kg x 10 = 41860 J adding them up total = 2339900 J

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