You have 350g of Aluminum Bromide (AlBr3) with a molecular weight of 266.6938 g/molIt is dissolved in water and the total volume of the solution is brought to 1.00LPlease explainThanks so much
find moles: 350g of (AlBr3) divided by 266.69 g/mol 1.312 moles AlBr3 since it was dissolved in 1 literyou have 1.312 Molar AlBr3 since 1 mole of AlBr3 has 1 mole Al 1.312 Molar AlBr3 releases 1.312 Molar Al +3 ions since 1 mole of AlBr3 has 3 mole Br 1.312 Molar AlBr3 releases 3 times as much 3.397 Molar Br -1 ions 1.312 Molar Al +3 ions + 3.397 Molar Br -1 ions 5.249 Molar in ions total your answer, rounded to 3 sig figs is 5.25 Molar in ions
