The hoist is to raise a 1135 kg mine cage at the rate of 4.6 m/sec. Mechanical efficiency of the hoist is 92%. What is the power in KW required to drive at their center.with solution...
Output Power = 1135 kg * 9.81 m/s^2 * 4.6 m/sec = 51218.01W =51.218kW Input Power = 51.218kW / 0.92 = 55.672 kW
