I remember a rule of thumb 30% of yield or proof?????
heritage ideas you wantat the same time as an merchandise is heated (or cooled), the quantity of warm temperature potential (Q) received (or lost) is calculated using Q mc?T the position m mass of merchandise c particular warmth potential of textile merchandise is created from ?T temperature replace operating in grams particular warmth potential of water 4.2J/(g?C) particular warmth potential of aluminium 0.9J/(g?C) (you should were given those values) _ A) call the purely excellent temperature at equilibrium TThe aluminium cup heats up from 15?C to TSo its temperature replace is T-15So it helpful factors an quantity of warm temperature potential Q1 mc?T one hundred ten x 0.9 x (T-15) The 110g of chilly water heats up from 15?C to TSo its temperature replace is likewise T-15So it helpful factors an quantity of warm temperature potential Q2 mc?T one hundred ten x 4.2 x (T-15) The 110g of further warm water cools from ninety?C to TSo its temperature replace is ninety-TSo it loses an quantity of warm temperature potential Q3 mc?T one hundred ten x 4.2 x (ninety - T) Assuming no warmth is lost ot the ecosystem, the nice and comfortable temperature received by technique of the field and chilly water (Q1+Q2) equals the nice and comfortable temperature lost by technique of the nice and comfortable water (Q3)Q1 + Q2 Q3 one hundred ten x 0.9 x (T-15) + one hundred ten x 4.2 x (T-15) one hundred ten x 4.2 x (ninety - T) Cancel out one hundred ten 0.9(T-15) + 4.2(T-15) 4.2(ninety - T) amplify the brackets 0.9T - 13.5 + 4.2T - sixty 3 378 - 4.2T deliver mutually the words 7.98T 454.5 T 454.5/7.ninety 8 fifty seven?C (have not checked my mathematics although) B) is performed in an identical waycall the necessary mass of water M, then Q1 mc?T one hundred ten x 0.9 x (50-15) Q2 mc?T one hundred ten x 4.2 x (50-15) Q3 mc?T M x 4.2 x (ninety-50) Then use Q1 + Q2 Q3 and artwork via the algebra/mathematics to locate M (in grams).
160 degrees celcius the Aluminum has double the specific heat therefore it will take double the time to reach the same temp as Ironif 2x80160 then double the hypothesis then 4x40160 achieving the same conclusion
