When 60.0 g of aluminum react with hydrochloric acid, how many grams of hydrochloride acid react?
I see no reason why it would have to be evenly distributedSince each muscle group does a different thing, it would make sense that they are more focused than evenly distributedCheers, Easymac79
Chemical equation of reaction: 2 Al + 6 HCl 2 AlCl3 + 3 H2 - divide the mass of aluminum by its molar mass: 60.0 g / 26.98 g/mol 2.22 mol (rounded to 3 sig digs) - the molar ratio between Al and HCl is 2:6 or 1:3 therefore, the number of mols of HCl is 32.22 6.67 mols - now multiply this number by the molar mass of HCl 6.67 mols (1.01g/mol + 35.45g/mol) 243 g Therefore, 243 g of HCl react with 60.0 g of Al
