I bought a new light that holds two light bulbs for my bathroom and quickly took off the old light. I then noticed that wall had three wires coming from it, a black, red, and white. The light however has four wires coming from it, 2 whites and 2 blacks. How do i wire this properly so both light bulbs can be turned on and off simultaneously?
cut the red wire i wonder if its like a spy movie u don't cut the light Colors or the dark ones either so cut the red 1!!!! it will be funny i u get eletricuted
I'm going to assume that you are in the U.S.A. (if not, then disregard the rest of my answer). On the new fixture, twist the ends of the black wires together and twist the ends of the white wires together. Connect the white fixture wires to the white wire in the wall (I hope it is in an electrical box). Connect the Black fixture wires to either the Black or Red wall wire. To determine which one, you will need to know which one is controlled by the switch on the wall. You could just pick one and see if it works. If it does not, then try the other wire. Do not use the cheap crappy wirenut connectors that usually come with these fixtures. Go to the hardware store and buy a pack of tan wirenuts (red will work if necessary.)
Since you have a black, red, and white wire coming out of the wall, this tells me you have a 3-way switch (meaning the light can be controlled by two different switches, correct?) If you only have one switch operating this light, then one of the wires may be (against building code rules) used as 'ground'. If only one switch is used with the light, then you'll need to switch the breaker off, then pull out the switch and see if a wire is attached to the green screw (ground). Black wire: Hot Red wire: Hot (three way circuit) White: Neutral Green or bare copper: ground
