1.) If 510 mL of 0.922 M aqueous Al2(SO4)3 and 750 mL of 0.307 M aqueous BaCl2 are reacted stoichiometrically according to the balanced equation, how many milliliters of 0.922 M aqueous Al2(SO4)3 remain? Round your answer to 3 significant figures.Al2(SO4)3(aq) + 3BaCl2(aq) → 2AlCl3(aq) + 3BaSO4(s) 2.) If 0.410 mol of gaseous Cl2 and 52.0 mL of liquid CS2 are reacted stoichiometrically according to the balanced equation, how many grams of liquid CCl4 are produced?CS2(l) + 3Cl2(g) → CCl4(l) + S2Cl2(l)
moles aluminium sulfate 0.510 x 0.922 0.470 moles barium chloride 0.750 L x 0.307 M0.230 moles aluminium sulfate needed 0.230/2 0.0767 moles in excess 0.470 - 0.0767 0.393 V 0.393 / 0.922 0.427 L 427 mL molarity of CS2 is needed
