6-pole motor, speed 8000 rpm, corresponding to the frequency converter output frequency is how much?
The synchronous speed of the motor is n = 60f / p
P is the pole pair number, and f is the power supply frequency.
The pole pair number of the 6 pole motor is 3.
Therefore, f = n * p / 60 = 8000 * 3/60 = 400Hz.
To 400HZ, so high frequency you tried it? I only tried 80HZ, if you tried, please tell me some of the high frequency of the actual situation will produce some changes in the motor,
Such a high speed estimated motor can not reach, to increase the gearbox
Specific algorithm: n = 60f / p
P is the number of pole pairs, f is the frequency.
The pole pair number of the 6 pole motor is 3.
F = n * p / 60 = 8000 * 3/60 = 400 Hz.
