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Question:

A 106 N sack of grain is hoisted to a storage room 54 m above the ground floor of a grain elevator.?

The rope being used to lift the sack of grain breaks just as the sack reaches the storage room. What kinetic energy does the sack have just before it strikes the ground floor?

Answer:

the answer is 5724 J for ALL questions.
work = force * distance so your force is 106 N times 54m = work Pe = mgh right? Newtons is already mg, so Pe = 105 * 54 Ke = 0.5mv^2 find your velocity using a motion equation and solve for the rest. You initial velocity is 0...you solve for the final

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