A 2.15 kg block of aluminum (specific heat 897 J/kg·K) is at an initial temperature of 300 KWhat will its final temperature be if 335,000 J of thermal energy are added?A) 474 K B) 174 K C) 803 K D) 447 K
Q mc(T2 - T1) Need T2 Q 335000 J m 2.15 kg c 897 J/(kg·K) T1 300K T2 - T1 Q/(mc) T2 T1 + Q/(mc) 300 K + (335000 J)/((2.15 kg)(897 J/(kg·K))) 473.7056337663011 K Which rounds to A) 474 K.
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