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A 4kg block of aluminium is( c 900j/kg/degree Celcius) at 450 degrees celcius is plunged quicky into a 20?

A 4kg block of aluminium is( c 900j/kg/degree Celcius) at 450 degrees celcius is plunged quicky into a 20L bucket of water (c 4180j/kg/degree celcius) initially at 20 degrees CelciusAssume 1That no water evaporates2That all of the heat transferred is used to increase water temp not the bucketCalculate te final temperatuer of aluminium and water mixture when the temperature stops changing.I am a new physics student so if you could include working much appreciated!!!!

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