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Question:

A 5.0-m long scaffold is 80 N. It hangs from wires at each end. A 200-N box sits 1.0 m from left. Tension?

What is the tension in each wire?a.Left wire = 40 N; right wire = 160 Nb.left wire = 200 N; right wire = 80 Nc.Left wire = 160 N; right wire = 40 Nd.Left wire = 240 N; right wire = 120 NThank You!

Answer:

The sum of the two tensions must equal the total weight supported so Tl + Tr = Wb + Ws = 200 + 80 where Wb is the weight of the box and Ws the weight of the scaffold. That's enough to choose the right answer, but to actually compute the tensions, you also need the torque equation. The sum of the torques around the left end of the scaffold must be 0 since the scaffold isn't moving. That means: 0 = (1.0) Wb + (2.5) Ws - (5.0) Tr where 1.0, the 2.5, and the 5.0 are the radii corresponding to the forces. So you can solve for Tr and then Tl.

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