The linear expansivity of copper is 19 x 10 to the power 10 minus 6 and its modulas of elasticity is 84 Gpa 1) determine the change in length that takes place 2) determine the change in diameter
No, it's not 19 x 10 to the power 10 minus 6 -- it's 19 x 10 to the power minus 6, better written as 19 x 10^(-6). Also, you omitted the units for the linear expansion coefficient. Presumably they're inverse Kelvin. I can't see that the modulus of elasticity has anything to do with the question, since we're not told of any stresses. #1. delta-L alpha L delta-T [19 x 10^(-6) /K] (500 mm) (110 K) 1.045 mm #2. delta-D [D*delta-L]/L 0.042 mm
