Home > categories > Construction & Real Estate > Cement > A concrete mix requires 2 parts sand and 3 part cement.How many pounds of sand are needed for 75 pounds of?
Question:

A concrete mix requires 2 parts sand and 3 part cement.How many pounds of sand are needed for 75 pounds of?

cement?a. 150 poundsb. 100 pounds c. 50 poundsd. 112.5 pounds

Answer:

the answer is C.
50 pounds
2/3 of 75 lbs = 50 lbs
Cement is 3 parts. Divide 75 by 3. And sand is 2 parts.So multiply the resultant by 2 75*2/3=50 pounds c is the right answer

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