A 150g piece of copper heated to 80°C is placed in the water. The water is stirred thorougly. After sufficient time elapses, to what temperature does the water change?Assume that no heat is transferred to or from the environment. The specific heat of water is 4.2 J/g.K , and copper's is 0.40 J/g.K
? Q1 = [m○(copper).cp(copper) + m(water).cp(water)]T1 Q2 = m(copper).cp(copper) T2 ? ??? Q1+Q2 = Q3 = [(m○(copper)+m(copper)).cp(copper) + m(water).cp(water)].T3 ; T3 > T1 → T3 = {[m○(copper).cp(copper) + m(water).cp(water)]T1 + m(copper).cp(copper).T2]/ [(m○(copper)+m(copper)).cp(copper) + m(water).cp(water)] → T3 =((0,1*400 + 0,2*4200)*20 + 0,15*400*80)/(0,25*400 + 0,2*4200) = 23,83 °C @+ ;)
