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Question:

A current of 0.6 A flows through an electrolysis cell for 300 seconds Calculate: i) The number of moles of?

electronsii) the mass of aluminum formed from the passage of this quantity of electricityPlease go step by step I'd like to understand.

Answer:

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There are several steps to this calculationFirst you need to calculate the amount of electricity that passes (in Coulombs) using:- Quantity of charge (Coulombs ) Current (Amps) x Time current flows (s) So Q (C) 0.6 x 300 180 C The second step involves the equation I mole of electrons 96,500 Coulombs of charge So we have 180/ 96,500 moles of electrons 0.001865 Moles or 1.865 x 10^-3 moles of electronsIn the third step you need to know the equation for discharge of Al 3+ ions Al 3+ + 3 e- Al So 1 mole of electrons will discharge only 1/3 moles of AlThe number of moles of Al discharged 1.865 x 10^-3 /3 0.622 X 10 ^-3 or 6.22 x 10^-4moles Al Last step(honest) 1 mole of any atom has a mass to the atomic mass of the atom(27g for Al) So mass of Al discharged 6.22 X 10^-4 x 27g 0.0168g
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