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Question:

A hydraulic hoist has an out put piston 30cm in diameter, and an input piston 1.0 cm in diameter.?

If a force of 70N is exerted on the input piston, what mass can be lifted by the output piston?

Answer:

Pin=Pout Force in / Area in = Force out / Area out Force out = (Force in / Area in ) * Area (in) Force out = (70/1)30 = 2100 N
About 50 kilos.

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