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Question:

A hydrogen-oxygen fuel cell operates on the simple reaction given below.?

A hydrogen-oxygen fuel cell operates on the simple reaction given below. H2(g) + 1/2 O2(g) H2O(l) If the cell is designed to produce 1.8 A of current, and if the hydrogen is contained in a 2.9 L tank at 200. atm pressure at 25°C, how long can the fuel cell operate before the hydrogen runs out? (Assume there is an unlimited supply of O2.) so i first used pvnrt and solved for n and got 23.71 moles but i dont know where to go from there

Answer:

gas cellular vehicles will probable be out quicker. no could have organic hydrogen in storage. some gas cells can cut up the hydrogen off of extremely available hydrocarbons like methane or LPG. in view that gas cells are greater desirable than two times as efficient as inner combustion engines human beings will ask your self how we ever have been given alongside with merely having a 4 hundred or so mile variety previously having to refuel.
EDIT: I calculated wrong. I believe the answer is correct now. Sorry about that. I'm no expert in chemistry, but I believe that the engine design for a 1.8 A output is what determines how fast it burns the fuel. For each H2-molecule burning there will be 2 electrons and 2 H+ ions. So, the important part here is of course the electrons. Let's see how many electrons passes through a current of 1.8 A each second: A current of 1.8 A has 1.8 Coulombs passing through it each second. That is equal to 6.24150948 * 10^18 * 1.8 1.1234717 * 10^19 electrons. This means to achieve a current of 1.8 A the engine has to burn (1.1234717 * 10^19) / 2 5.6173585 * 10^18 H-molecules per second. You have calculated that you have 23.71 moles of H2-molecules, right? This is equal to 23.71 * 6.02 * 10^23 1.4273 * 10^25 molecules. With that ammount, the engine can run for (1.4273 * 10^25) / (5.6173585 * 10^18) 2,540,874 seconds, which is approximately 705.8 hours. Again, I'm no expert and I calculated this rather quick so there is a chance this is wrong. You should review this and calculate it again yourself! Numbers I've used are: Avogadro's Constant: 6.02 * 10^23 Electrons per Coulomb: 6.24150948 * 10^18

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