A parallel-plate capacitor is made by placing polyethylene ( 2.3) between two sheets of aluminum foilThe area of each sheet of aluminum foil is 430 cm2, and the thickness of the polyethylene is 0.2 mm.The permittivity of free space is 8.85 × 10?12 C2/N · m2Find the capacitance Answer in units of nF.
you should give the density of aluminum use formula Mass Volume x density
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the mass of the foil in question 8 oz 0.5 lb Assuming the density of Aluminum to be 169 lb/cft (standard value) that is a mass of 169 lb will have a volume of 1 cubic-feet So a mass of 0.5 lb will have a volume of 0.5 / 169 0.002958579 cubic feet area x thickness volume thickness volume / area thickness 0.002958579 / 50 thickness 0.000059171 feet
Use the usual formula: C Area x epsilon / distance between the plates, except here, epsilon permittivity of free space x dielectric constantAlso, it's given that the polyethylene completely fills the space between the plates, so that distance between the plates is the same as the thickness of the polyethylene
