AP Chemistry question. Thank you.
If the iron ore is 73% Fe2O3, then from a 1000 g sample of the ore you will have 730 g of Fe2O3. moles of Fe 730 g Fe2O3[(1 mole)/(159.69 g/mol)](2 moles Fe)/(1 mole Fe2O3) 4.57 moles Fe mass Fe 4.57 moles Fe(55.845 g)/(1 mol) 255 g Fe. Hope this is helpful.
Always when I post a question, even if it's the simplest one, nobody can provide me a proper informed answer on this site. Wtf happened to people who actually make the effort to answer?
Always when I post a question, even if it's the simplest one, nobody can provide me a proper informed answer on this site. Wtf happened to people who actually make the effort to answer?
