What is the thickness of the foil in millimeters? (Density of Al 2.699 g/cm3.)please explain process
We know that: 1 cm^3 1 mL 1000 mL 1 L 1 lb 453.59 g From the problem, we're given that: 21 cans 1 lb We're also given the density of aluminum, which is 2.70g/cm^3 In the problem, the students collected 125 cans, so we need to first figure out the mass of aluminum those cans have125 cans (1 lb / 21 cans) 5.95 lb We can multiply by 1 lb/21 cans because they are equal, and thus it's just another name for 1Multiplying by 1 doesn't change anything, but it does allow us to convert the units! Now that we know how much the cans weigh, we have to figure out the volume of that much aluminum, so we need to use the densityAt the same time, our density is in g/cm^3 but we have our mass of the cans in pounds, so we're going to need to do some unit conversion (the same way as we did earlier, by multiplying by another name for 1)(5.95 lb)(453.59 g / 1 lb)/(2.70g/cm^3) 999.58 cm^3 Of course, we need liters, not cm^3, so we convert again (or we could have just done this in the above step too!): 999.58 cm^3 (1 mL / 1 cm^3) (1 L / 1000 mL) 0.99958 L Obviously, 0.99958 L is approximately 1 LHope this helps.
1 sq ft 929 sq cm 3.636 grams / 2.699 g/cm3 1.347 cm3 1.347 cm3 / 929 cm2 0.00145 cm thickness
