(given the fact that specific gravity of aluminum is 2.7)1. What is its volume?2. The ingot is suspended from a rope and totally immersed in water. What is the tension in the rope (the apparent weight of the ingot in water)?
first find the volume of your aluminium. youll need this when analyzing the bouant force F(b). the sg of aluminum is 2.7 and the density of water is 1000 kg/m^3 so the density of aluminum is 2.7x1000=2700kg/m^3. the mass is 71N/g = 7.237512742 kg. so volume of our piece of aluminum = mass/density = 0.0026805603 m^3 now analyze the forces being applied to the system. There are three, the force of gravity F(g), the buoyant force F(b) and the tension T. Tension and buoyant force push up, gravity pulls down. the system will be at rest since the rope is holding it at rest. so T + F(b) - F(g) = 0 T + (Volume aluminum X density water X g) - (MAss of aluminum x g) = 0 T + (0.0026805603x1000x9.81) - (71 N (given in problem)) = 0 Solving for T, T = 44.70370346 N = 45 N using sig figs.
