A standard involute spur gear, when the root circle and the base circle coincides with the number of teeth is? If the tooth number is greater than the number of teeth, tooth root and base circle which is bigger?It is said to be 41.We are studying the fundamentals of mechanical design41 how come?
If the number of teeth is greater than this value, the root circle is larger than the base circle, such as 45, then db=42.3m (mm), df=42.5m (mm), and z>41.45 can be deduced according to df>db
And take ha*=1, c*=0.25, alpha =20 degrees, then there is Z (1-cos20) =2.5, get z=41.45
The diameter of the base circle is db=mzcos alpha, while the diameter of the root circle is df= (z-2ha*-2c*) M., which makes the two equal