1. The additive inverse of a complex number z is a complex number a such that z + a = 0. What is the additive inverse of the complex number -2+4i ?2. The multiplicative inverse of a complex number z is a complex number m such that z ? m = 1. What is the multiplicative inverse of the complex number 1 - i ?I'm confused on how to do this and it would help if anybody could explain because i have a final over this tomorrow. THANKS
1. Additive inverse: To find the additive inverse find what the number added to will equal zero. So basically, set up an equation to finda." z+a=0 -2+4i+a=0 a=2-4i And so the additive inverse of -2+4i is 2-4i. (notice that it was simply the originally number multiplied by -1). 2. Multiplicative inverse: Basically the same thing only the two numbers are multiplied. z*m=1 (1-i)*m=1 m=1/(1-i) So that's the answer. I suppose you should probably simplify it though. 1/(1-i) * (1+i)/(1+i) [multiply by the conjugate of the denominator to get the complex number out of the denominator). (1+i)/(1-i?) (1+i)/(1--1) (1+i)/2 So that's you're answer.
