Can somebody help me make a symbol equation of this?
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Al(s) + Ba(NO3)2(aq) - no reaction If you place a piece of aluminum metal into a solution of barium nitrate nothing will happenJust because someone writes an equation on paper, doesn't meant that it will actually occur in practiceAluminum is below barium in the activity series, which tells us that aluminum metal cannot reduce barium ionsTherefore, there is no AlCl3(aq) and Ba as you might have expectedIf Ba metal was produced we could not have left it simply as Ba(s)It would have reacted with water to make Ba(OH)2(aq) and H2 gas Follow up Here is perfect example of why you must specify the states of the compounds and the conditionsIn solution, the nitrate ion does nothing, but when aluminum powder is combined with solid barium nitrate powder then a reaction can occur between the aluminum metal and the decomposing barium nitrateIndividual reactions: 2Ba(NO3)2(s) -Δ- 2BaO(s) + 4NO2(g) + O2(g) 4Al(s) + 3O2(g) - 2Al2O3(s) Overall reaction: 2Al(s) + 3Ba(NO3)2(s) - 3BaO(s) + 6NO2(g) + Al2O3(s)
