Assume that one aluminum can is completely reacted with oxygen to produce aluminum oxide, and that this energy can be completely converted to electrical energyHow long could this energy keep a 60 Watt light bulb burning?Al 26.98 g/moleO 16 g/moledelta Hf (Al2O3) 1670 kJ/moeone can 14g1 watt 1 J/secany help would be greatly appreciated!
find moles: one can is 14 grams Al 26.98 g/mol 0.5189 moles of Al the reaction 2 Al 3O2 - 1 Al2O3 (s) is a formation reaction, whose dH -1670 kJ/mole find energy released: 0.5189 moles of Al 1670 kJ/mole 868.1 kJ released aka 868,100 Joules find watt-seconds: 868,100 Joules released 1 watt-sec / joule 868,100 watt-sec find seconds: 868,100 watt-sec 60 watt bulb 14,468 seconds find minutes: 14,468 seconds 60 sec / min 241 min find hours: 241 min 60 min / hour 4.02 hours your answers, rounded to 2 sig figs would be: 14,000 seconds 240 min 4.0 hours ( the 14 g can had only 2 sig figs)
