A method for recycling scrap aluminum converts it to alum [potassium aluminum sulfate dodecahydrate, KAl(SO4)212H2O].What is the maximum amount of alum (in metric tons) that can be prepared from 2.32 metric tons of scrap aluminum (1 metric ton 1000 kg)? Answer is 40.7 but I have no clue how to solve this problem.
Why do you need CO2 at this pressure? Why do you need to use aluminum? Have you actually calculated any of the pressure you mention or any of the pressures involved? Do you realize that the amount of dry ice and the size of the tube are things you need to use to make these calculations? Do you have any idea about strength of materials and strength changes with temperature? Getting careful answers from Yahoo is not what you want to rely on to protect yourself or othersIf you are working to make the Darwin Award, that's one thing and it is a free country (at least where I live), just be sure you don't hurt anyone else.
1 mole of KAl(SO4)212H2O has 1 mole of Al so using molar masses: 2.32 metric tons Al (474.39 g/mol KAl(SO4)212H2O / ( 26.98 g/mol Al) 40.79 metric tons I get 40.8 metric tons differing only on how one rounds off whem adding up the molar masses (p.sthe (g/mol) / (g/mol) molar mass units cancel out , leaving you with units of metric tons)
