An engine that weight 350 lbs is removed from an a/c by means of a mobile hoist the engine is raised 3 ft above its attachment mount entire assembly is then moved forward 12 ft. A constant force of 70 lbs is required to move the load hoist. What is total work input required to move hoist Answer options….a.840 ft lbsb.1890 ft lbsc.1050 ft lbs
The work done as the engine is raised = weight * height = 350 * 3 The work done as the engine is moved = force * distance = 70 * 12 Total work = 350 * 3 + 70 * 12 Leter c
