An ore contains Fe3O4 and no other iron. The iron in a 41.07 gram sample of the ore is all converted by a series of chemical reactions to Fe2O3. The mass of Fe2O3 is measured to be 34.7 grams. What was the percent Fe3O4 in the sample of ore?Answer in units of %
Running the fuel pumps (there are 2 of them) dry is likely the cause of the check engine light.
Do this exactly like the other one. 2Fe3O4 will give 3Fe2O3 [ continuity of iron atoms to each compound] molar mass Fe3O4 is 232 molar mass Fe2O3 is 160 The relationship tells you 160 x 3 480g Fe2O3 comes from 232 x 2 464g Fe3O4 now use simple proportion to get answer 34.7g Fe2O3 comes from 464/480 x 34.7g Fe3O4 lets call this y gram so percent Fe3O4 mass Fe3O4/ ore mass x 100 y/41.07 x 100
34.7 g Fe2O3 34.7/159.7 moles 0.217 moles 0.435 moles Fe, which are 0.435/3 moles 0.145 moles Fe3O4 0.145*231.54 g 33.54 g Fe3O4. 33.54g 33.54*100/41.07 % 81.66 % by mass OG
Check t it is not on secure or is loose it will set off the check engine light
If you ran out of gas the engine would of recognized misfires and shutoff thoses cylinders and tripped the check engine light on. It may be just a matter of having the fault codes erased. You have warranty, go to a benz dealer.
