What mass of iron can be obtained from 54.0g of this ore?Express your answer to three significant figures and include the appropriate units.
Ive built a bike using wheelchair rims as and rubber tubeless tires that came originally for both front and rear tires on my fixie.
I think one or more of your friends are out to make a quick $20 for a bogus answer. And why would you even want a wheelchair wheel on a bicycle?
They are pulling your leg, just get a regular front wheel. The axle on wheel chair hubs are only supported at one end so they need to have a much larger axle.
I'm sorry I don't know about this
Answer Molar mass of Fe2O3 159.6 g / mol, [ 55.8*2+48 159.6] Molar mass of Fe 55.8 g / mol The given ore has 15% Fe2O3, therefore 100 g of this ore has 15g Fe2O3 which is 15*[ 2*55.8 /159.6 ] 10.5 g iron therefore 54 g of this ore will have , 0.54*10.5 5.723 g iron
Ive built a bike using wheelchair rims as and rubber tubeless tires that came originally for both front and rear tires on my fixie.
I think one or more of your friends are out to make a quick $20 for a bogus answer. And why would you even want a wheelchair wheel on a bicycle?
They are pulling your leg, just get a regular front wheel. The axle on wheel chair hubs are only supported at one end so they need to have a much larger axle.
I'm sorry I don't know about this
Answer Molar mass of Fe2O3 159.6 g / mol, [ 55.8*2+48 159.6] Molar mass of Fe 55.8 g / mol The given ore has 15% Fe2O3, therefore 100 g of this ore has 15g Fe2O3 which is 15*[ 2*55.8 /159.6 ] 10.5 g iron therefore 54 g of this ore will have , 0.54*10.5 5.723 g iron
