Question:
Approximately how much volume of water will a 1 inch (dia.) copper pipe deliver under 90 lbs. of pressure?
I have looked at charts and they give the answer based on one foot per minute velocity in pipe or tube. How does that translate to 90lbs. of pressure? Can someone just give me an approximate volume so I can figure out how much water (over time) I am adding to my swimming pool every day. I think I may have a leak and I want to decide weather it will be more feasible to excavate the lines or keep filling it daily until the season is over. Thanks for your simple answer.
Answer:
Like the others have said, it's no problem. You will see more benefit from intake mods now though.
no but it would be good to upgrade to a cold air intake!!! stock exhaust aftermarket exhaust all release the same amount of gasses, its just the aftermarket system allows it to flow more freely, and louder. increases HP torque and gasmilage
It is the pressure drop that causes flow. The length of pipe, number of bends and fittings and the roughness of inside surface all play a part in the flow rate. When you say 90 lbs (PSI?) it is presumably at the supply point that may be some distance away from the delivery point. Difficult to calculate unless more details are given. May be simpler to measure time to fill a bucket or drum and extrapolate.
You're trying to find out how much water you're adding to your pool every day, but what do you know? You know you have 90psi in the water supply, but does that supply end in some kind of nozzle, or is it just a 1 pipe that goes directly into the pool? Velocity at an outlet with a certain amount of pressure can be calculated by the following formula, which relates the pressure (force per unit area, or F/A) on the left with mass flow-rate (mdot) and outlet velocity (V), on the right: F/A mdot*V/A ρAV*V/A ρV^2 Density of water: ρ 1.937 slugs/ft^3 Pressure of 90 pounds per square inch: F/A 90*144 12,960 lb/ft^2 ρV^2 v 81.8 ft/sec So if the pressure of 90 psi is maintained at the outlet, you'll get about 82 ft/sec water velocity, which for a 1 diameter outlet comes out to about 12,000 gallons per hour! However, because 82 ft/sec is a pretty large water speed, I think it's unlikely you'll be able to maintain that kind of pressure to the end of a 1 pipe, in other words the speed of the water in the pipe prior to the outlet will cause enough friction on the inside of the pipe that the pressure of 90 psi isn't maintained all the way to the outlet.
Like the others have said, it's no problem. You will see more benefit from intake mods now though.
no but it would be good to upgrade to a cold air intake!!! stock exhaust aftermarket exhaust all release the same amount of gasses, its just the aftermarket system allows it to flow more freely, and louder. increases HP torque and gasmilage
It is the pressure drop that causes flow. The length of pipe, number of bends and fittings and the roughness of inside surface all play a part in the flow rate. When you say 90 lbs (PSI?) it is presumably at the supply point that may be some distance away from the delivery point. Difficult to calculate unless more details are given. May be simpler to measure time to fill a bucket or drum and extrapolate.
You're trying to find out how much water you're adding to your pool every day, but what do you know? You know you have 90psi in the water supply, but does that supply end in some kind of nozzle, or is it just a 1 pipe that goes directly into the pool? Velocity at an outlet with a certain amount of pressure can be calculated by the following formula, which relates the pressure (force per unit area, or F/A) on the left with mass flow-rate (mdot) and outlet velocity (V), on the right: F/A mdot*V/A ρAV*V/A ρV^2 Density of water: ρ 1.937 slugs/ft^3 Pressure of 90 pounds per square inch: F/A 90*144 12,960 lb/ft^2 ρV^2 v 81.8 ft/sec So if the pressure of 90 psi is maintained at the outlet, you'll get about 82 ft/sec water velocity, which for a 1 diameter outlet comes out to about 12,000 gallons per hour! However, because 82 ft/sec is a pretty large water speed, I think it's unlikely you'll be able to maintain that kind of pressure to the end of a 1 pipe, in other words the speed of the water in the pipe prior to the outlet will cause enough friction on the inside of the pipe that the pressure of 90 psi isn't maintained all the way to the outlet.
EDIT I agree with AVR and there is no simple answer with the information at hand. So how long is the hose in the example ? How long is the 1 pipe after the 90 psig gage ? My design tables for piping max out at around 30gpm for 1 pipe, a little less for 1 OD tube. Perhaps theoretical water flow at the limited (choked flow) sonic velocity in a 1 pipe is about 200 gpm. (I am still working on it) So my guess is 50 gpm. But look at that high 90psig service pressure in your house. That 90 psig has no direct bearing on this particular flow problem. If you suspect a leak and you are on a municipal water supply, turn off all the other water usages for a couple hours and check the water meter reading. Call the utility for the method of conversion. You mention filling it. I hope you don't mean the whole thing. You can calculate the water loss by noting the change in level in a 24 hour period and doing the simple math. (Also, if you have a notable leak, it should be showing up in the yard somewhere.) Now for the pressure - - If you have 90 psig domestic water pressure , that is about double what is usual. How are your faucet seats holding up ? Do you experience water hammer ? You may need a pressure reducer or a replacement of the deffective one you already have.