Assuming the copper in the penny is Copper-68 and using the knowledge of radioactive emissions. Write a complete balanced nuclear equation that will demonstrate the transmutation of the copper when is undergoes:A. Alpha emissionB. Beta emissionC. Gamma emission
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Copper-68 is most likely going to decay by beta decay, but a metastable nuclear isomer exists that may be able to decay by either gamma emission or internal conversion. Alpha emission is improbable or impossible, but it's possible to specify a formula even if the probability is zero. The alpha process would be Cu-68 -> Ni-68 + He-4 + The beta process would be: Cu-68 -> Zn-68 + e- + -v(e) That is, copper-68 turns to zinc 68, one electron, and one electron-antineutrino. The gamma emission (for the nuclear isomer) would be: Cu-68 -> Cu-68 + gamma The internal conversion (for the nuclear isomer) would be: Cu-68 + e- -> Cu- + e- (The initial e- would be a ground state electron, while the resulting e- would be a high-energy electron.) The notation above isn't quite standard, due to limitations of plain text. Check my references to see standard notation. Finally, what does a penny have to do with it? Given the short half-life of Cu-68, it would be pretty difficult to get enough of it to make anything out of it that was big enough to see.
