Bauxite ore contains aluminum oxide, which is decomposed using electricity to produce aluminum metal and oxygen. What mass of aluminum metal can be produced from 125 g of aluminum oxide?I'm really confused and I need help. Thanks.
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Aluminum Oxide is put together from aluminum and oxygen. A quick look at the periodic table tells you that Al has a +3 charge, while O has a -2 charge. Thus the formula must be Al2O3. Now, the atomic mass of Al is 26.982, and of O 15.999. This means that there is that many grams of each in one mole of each respective element. Thus the formula Mass of Al2O3 is 2(26.982)+3(15.999) = 101.961 g Al2O3. There are 2 mols of Al, so 2(26.982) = 53.964 g Al per the formula mass (53.964/101.961). Now that you have a ratio for the amount of Al in Al2O3, simply multiply it by the mass of aluminum oxide you have to get the mass of Aluminum out. Thusly: (53.964/101.961) x 125g = 66.157 g Al Ta-da!
That's a good question, I was wondering the same thing myself
