1g of a sample of iron ore was dissolved in H2SO4 in a titration vessel yielding Fe2+. This solution was titrated using 0.1M KMnO4.The analysis was repeated five times with the following titration volumes:3.0, 3.8, 3.1, 3.2 and 3.3ml.Calculate the average iron ore content in the ore as a mass percentage.Aw(Fe) 55.84 gmol-1
MnO4- + 5 Fe2+ + 8H+ Mn2+ + 5 Fe3+ + 4 H2O volume 3.0 + 3.8 + 3.1 + 3.2 + 3.3 / 53.3 mL moles MnO4- 0.0033 L x0.1 M 0.00033 moles Fe2+ 5 x 0.00033 0.00165 mass Fe 0.00165 x 55.84 g/mol0.0921 g % 0.0921 x 100 / 1 9.21
