For the reaction 2Al(s) + 3Br2(l) → 2AlBr3(s) ΔSo is equal to -144 J K-1Use this value and data from Appendix A of Blackman to calculate the value of So for solid aluminium bromide (in J K-1 mol-1)
we don't have access to Appendix A of Blackman so you may need to use your data, if it varies from the standard entropy data which I obtained from; bilbo.chm.uri.edu/CHM112/tables/tstandard entropy of Al(s) 28.3 J/mol-K standard entropy of Br2(l) 152.23 J/mol-K ΔSo S products - reactants ΔSo [(2) (S of AlBr3(s)] - [(2) (28.3) (3) (152.23)] -144 J K-1 [(2) (S of AlBr3(s)] - [(56.6) (456.69)] -144 J K-1 [(2) (S of AlBr3(s)] - (513.29) -144 + 513.29 [(2) (S of AlBr3(s)] 2 S of AlBr3(s) 369.29 S of AlBr3(s) 184.645 your answer, rounded to 1's decimal place would be So for solid aluminium bromide 185 J K-1 mol-1
thank you for the above informationThen why are they so HARD to clean?
