Ok so this question popped up on my homeworkI've got a test tonight so it's too late to learn this before exam (the book doesn't even show this type of problem) but can someone help me for the assignment at least? (not due til Monday) I don't need the answer for the problem just how to set it up thanks.
Diameter (in cm) when the temperature of the plate is raised to 140.7°C 2.360 cm + 2.360 cm 23.00 x 10-6 /C° (140.7°C - 0.000°C ) 2.360 cm ( 1 + 23.00 x 10-6 /C° 140.7°C ) 2.360 cm 1.0032361 2.367637196 cm
find moles using molar mass: 19,.2 g Al 26.98 g/mol 0.7116 moles of Al by the equation: 3 I2 2 Al 2 Al I3 0.7116 moles of Al reacts with 1.5 times as many moles of I2 1.067 moles of I2 using molar mass 1.067 moles of I2 253.81 g/mol 270.93 grams of I2 your answer, rounded to 3 sig figs is 271 g I2
Diameter (in cm) when the temperature of the plate is raised to 140.7°C 2.360 cm + 2.360 cm 23.00 x 10-6 /C° (140.7°C - 0.000°C ) 2.360 cm ( 1 + 23.00 x 10-6 /C° 140.7°C ) 2.360 cm 1.0032361 2.367637196 cm
find moles using molar mass: 19,.2 g Al 26.98 g/mol 0.7116 moles of Al by the equation: 3 I2 2 Al 2 Al I3 0.7116 moles of Al reacts with 1.5 times as many moles of I2 1.067 moles of I2 using molar mass 1.067 moles of I2 253.81 g/mol 270.93 grams of I2 your answer, rounded to 3 sig figs is 271 g I2
