Calculate the mass in grams of Iodine (I2) that will react completely with 20.4 g of aluminum to form aluminum oxide (AlL3)
actually the guy before me did it right but made a mistake at one point 0.07 mole is the # of moles of Al which needs to be changed to moles of product, and then back to find mole of iodide. once thats found then you can use the MW to change it to grams.
Aluminium oxide? Shouldn't it be Aluminium iodide? 1. Form a balanced equation 3I2 + 4Al - 2Al2I3 2. Number of moles of Al 20.4/(Mr of Al) = 20.4/27 = 0.7555mol 3. Number of moles of I2 0.7555/4 x 3 = 0.5666mol 4. Mass of I2 required = 0.5666 x Mr of I2 = 0.5666 x (127x2) Ans: 143.9164g
