How many kilograms of limestone should be added for every kilogram of iron ore processed in a blast furnace if the limestone is 98.00% pure and the iron ore contains 7.80% SiO2 by mass? (Note: SiO2(s) + CaCO3(s) -- CaSiO3(s) + CO2(g))
limestone is CaCO3 hints 1 mole CaCO3 per 1 mole SiO2. convert that to kg CaCO3 / kg SiO2 7.8% by mass means 7.80 kg Si / 100 kg iron ore 98% pure means 98 kg CaCO3 / 100 kg limestone solution mw CaCO3 100.1 g/mole 100.1 kg / kmole mw SiO2 60.1 g/mole 60.1 kg / kmole from balanced equation. 1 kmole CaCO3 / kmole SiO2 x (100.1 kg CaCO3 / kmole CaCO3) x (1 kmole SiO2 / 60.1 kg SiO2) 1.666 kg CaCO3 / kg SiO2 still with me? 1.666 kg CaCO3 / kg SiO2 x (100 kg limestone / 98 kg CaCO3) x (7.80 kg SiO2 / 100 kg iron ore) 0.133 kg limestone / kg iron ore
