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Question:

Can anyone help me on this algebra problem. I am stuck?

A contractor purchases a bulldozer for $36,500. The bulldozer requires an average expenditure of $5.25 per hour for fuel and the operator is paid $11.50 per hour. (A)Write the equation giving the total cost of operating the bulldozer for (t) hours, remember to include the cost of the bulldozer. (B)If the customers are charged $27.00 per hour to use the bulldozer, write the equation for the revenue if it used for (t) hours. (C) Write an equation that will show the profit from (t ) hours. Note: Profit= Revenue-cost(D) How many hours of use would the bulldozer need to be used to break even?Thanks

Answer:

(A) cost = 36500 + 5.25t + 11.50t .. cost = 36500 + 16.75t ... collect terms (B) Revenue = 27.00t (C) Profit = Revenue - cost .. Profit = 27.00t - (36500 + 16.75t) .. Profit = 10.25t - 36500 (D) At the breakeven point, profit is zero. .. 0 = 10.25t - 36500 .. 36500/10.25 = t .. 3561 = t The contractor needs to sell 3561 hours of bulldozer use to break even.

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