OkIf you could give me the steps you took and the correct answer so I can understand what I'm doing from now on that would be great!!Here's the question:A rectangular piece of aluminum foil measures 13.72 cm x 8.63 cm and has a mass of 3.1 gFind how thick it is(VLxWxH)Please take in to consideration the correct amount of significant figures.THANK YOU!!!
Get a polish called Flitz will look like chrome when your done
rouge a buffing wheelrouge is the stuff you pot on the wheel that does the buffing.
Try some 0000 steel wool.
Start by sanding it with 200 grit or higher sand paper Next go to 400 grit, then 600 grit both of which should be wet sandedFollow that with buffing compound to remove most of tiny scratches and end with polishing compound.
We have two main equations1) The one you gave: V LWHWe are given L 13.72cm and W8.63cm, and we are asked to find HWe are also given the mass of this sheetWouldn't it be nice if we could relate mass to volume? 2) m dV, or Mass Density VolumeAll we need now is the density of aluminumThe link below suggests that aluminum has a density of 2.7g/cm? , so (substituting this for d and 3.1g for m) we find 3.1g (2.7g/cm? ) V V 1.1cm? We take this back to equation (1) and find: 1.1cm? 13.72 cm 8.63 cm H H .0097 cm, which you might rewrite using, say, micrometersAs for significant figures: I kept 2 sig figs because that's how many you gave in 3.1 g, the lowest precision in the problemIf I were really worried about error propagation - disclaimer: I'm not a scientist - I would let each measurement vary to the limits of its own precision, and see how the final answer behavesFor instance, the mass reported as 3.1g could really be anywhere from 3.05 to 3.15gRearranging (1) and (2) together, I find: H V / (LW) m / (LWd)In order to maximize computed H, I would use maximal m and minimal L, W, dThat happens when m 3.15g, L 13.715cm, W 8.625cm, and d 2.65g/cm?In this case, I get H 0.0100487 cm, roughlyIn order to minimize computed H, I would use minimal m and maximal L, W, dThat happens when m 3.05g, L 13.725cm, W 8.635cm, and d 2.75g/cm?In this case, I get H 0.0093582 cm, roughlySo, the actual thickness is somewhere between these two extremes0.0097cm is not too far from the middle of the range.
