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Question:

can someone please help with this chem question?

A piece of aluminum foil measuring 3.60 mmby 3.64 mmhas a mass of 0.702 gAluminum has a density of 2.70 g/ccWhat is the thickness of the foil in mm.?

Answer:

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First, know that 1 cc 1 cm^3 Next, convert your other measurements into cm: 3.60 mm 0.360 cm 3.64 mm 0.364 cm You'll need these for laterNext, you need to find the volume of the piece of aluminum foilFind that using this formula: density mass/volume 2.70 g/cm^3 (0.702 g)/(volume in cm^3) volume 0.260 cm^3 Now, think of your sheet as like a flattened boxThe volume of this box would be given by: volume of box (length) x (width) x (height) We'll think of height as the thickness in this case, they thing we are trying to solve forNow just plug and chug your numbers to solve for height: 0.260 cm^3 (0.360 cm)(0.364 cm)(? cm) 0.260 cm^3 (0.131 cm^2) (? cm) ? 1.98 cm -height or thickness of the foil And since there are 10 mm in 1 cm, simply multiply this thickness (in cm) by 10 to get thickness in mm: (1.98 cm) x (10 mm/1 cm) 19.8 mm -thickness of the foil Hope that helps!

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