I am starting pre-algerbra in my 6th grade class, and I need your help. Here is the problem, I can't skip any steps or do shortcuts to solve it.3[6(12-3)] -17Here is the part I am stuck on. Once I subtract 12-3 (parenthesis first) what do I do with the brackets? Leave them or change them into parenthesis?
What do you mean? . First you subtract 12 from 3. Then, you multiply 6 to your answer. After, you multiply 3 to your answer. Finally, take your answer and subtract 17 from it. 12 - 3 9 6 * 9 54 54 * 3 162 162 - 17 145
first subtract 12 and 3, then multiply that by 6, then multiply that answer by 3, and subtract 17
do the parenthesis first and then do the brackets it would be like this 3[6(12-3)] -17 3[54] -17 162-17 145
parenthesis first then do whats inside the brackets so so 12-39 3[6(9)]-17 3[54]-17 the brackets around the 54 mean nothing. the only way you would use them is if you have a negative number. if you had a negative number you would just change it to make it positive. 162-17 145
Brackets are functionally equivalent to parentheses. They have to match though . . . [2) is not a valid expression. You simplify by going from the innermost expression to the outermost. For example: [([((5+1)*2)/2]+1)+17] [([(6*2)/2]+1)+17] [([12/2]+1)+17] [(6+1)+17] [7+17] 24 Good night!
