2 Al2O3 (s) -gt; 4 Al (l) + 3 O2 (g)Calculate the mass of aluminum oxide reacted if 385 g of Al was produced and the percent yield was found to be 89.3%.I got 727g but the answer is 815g, is the answer wrong?Please show how you get the answer for this problem, thank you!
It looks like you used the correct calculation, except you didn't factor in the % yieldIt would only require 727g Al2O3 if the yield were 100%Since the yield is 89.3%, you need to divide 727g by 0.893, giving you 814gIf you use atomic masses right from a periodic table (without rounding them), you'll get 814.6g, which rounds to 815g.
