My class did a lab about synthesizing alum using the equation:2Al + 2KOH +4H2SO4+ 22H2O -gt; 2KAl(SO4)2 x 12H2O + 3H2The question i'm having trouble with is:Calculate the minimum volume of 5.0M H2SO4 that the student must use to react completely with 2.7g of aluminum metal.
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40 ml (round up to 45 ml to compensate for kenetics mixing/contact inefficencies.) 2.7g Al 0.1 moles 2 moles H2SO4 per mole Al 0.20 5 Moles H2SO4 per liter water 0.20/5 0.04 liters 40 ml
